In 1962, the year Ban LO won his Hanoi championship, the son of a local master challenged him to give odds of two moves. LO won three games in a row.
These are classic examples of master/student play. This kind of practice naturally corresponds to the study of Ming Dynasty theory. The key question is always how Red either keeps or loses the advantage.
Game 1
In the first game, Red chooses to take the central pawn, and tries to build a solid position.
| RED |
unknown |
|
| BLACK |
Ban Lo |
|
| DATE |
1962 |
|
| PLACE |
Hanoi |
|
Comments by Bill Brydon, with help from Ban LO.
See the game in a
java viewer,
algebraic or
WXF
notation.
1. C2=5 ....
2. H2+3 C8=5
3. C5+4 ....
According to LO, taking this pawn is wrong in an even game, but OK when Red has an extra move.
3. .... A6+5
4. E3+5 H8+7
5. C5-2 R9=8
6. H8+9 H2+3
7. A4+5 C2=1
8. R1=4 R1=2
9. C8=6 H3+5
10.R4+6 R8+6
11.C5=3 H5+4
12.C6+1? ....
Lo says that 11. C5=3 is fine, but that 12. C6+1? loses Red’s advantage, and is refuted by 12. R2+8.
12..... R2+8
13.R4=3 R2=4
Red should retract with 14. C6-1, but wrongly accepts Black’s sacrifices, and loses the game.
14.C3+3 C1=7
15.R3+1 R4-2
16.R3+2 A5-6
17.R9+1 R8+1
18.H3-4 R4=5
19.R3-5 H4+6
20.R3=4 H6+7
21.R4-3 R5=6
22.R4=3 R8+2
Game 2
In the second game, Red constructs a weak attacking position, and can’t handle Black’s counter-play. The opening is less clear than in game one, so the question of where Red lost his advantage is less easy.
| RED |
unknown |
|
| BLACK |
Ban Lo |
|
| DATE |
1962 |
|
| PLACE |
Hanoi |
|
Comments by Bill Brydon, with help from Ban LO.
See the game in a
java viewer,
algebraic or
WXF
notation.
1. C2=5 ....
2. H2+3 C8=5
3. R1+1 H8+7
4. R1=6 A6+5
5. R6+7 H2+3
6. R6-2 ....
Lo says that 6. R6-2 is OK: "Some people play this way"
6. .... C5=6
7. P7+1 R9=8
8. A6+5 C2+4
9. P3+1 E7+5
In a practice game, I gained a winning advantage with (see the variation in a
java viewer) 10. H8+7 R8+4; 11. H7+8 C6+4 12. C5=7 P7+1 13. P3+1 R8=7 14. E7+5 H7+6 15. R6+2 R1+1 16. R9=6 R1=4 17. R6+8 H6-7 18. H8+7 C2=3 19. H7+5 C6-5 20. H5+3 H7+6 21. R6-5 R7-3 22. R6=7. Two hours later, he escaped with a draw.
10.C8=7 R8+4
11.H8+9 R1=2
12.R9=8 P7+1
13.P7+1 P7+1
14.P7+1 R8=3
15.C7=6 P7+1
16.H3-2 H7+6
17.R6+2 R3-1
18.P9+1 R3+2
19.R6-5 C2=5
20.R8+9 R3+4
21.C6-2 H3-2
22.H2+1? C6=7
In the final position, Black threatens mate, and 23. H1-3 will be crushed by 23... P7+1.
0-1
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